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2 years ago

What is (4x - 3)^6 expanded

Mathematics

1 answer:

fenix001 [56]2 years ago

4 0

Expad the expression:

4096x^(6)-18432x^(5)+34560x^(4)-34560x^(3)+19440x^(2)-5832x-729

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Find the mean and median of these data: 2, 4, 10, 12, 18, 20.

UNO [17]

The mean of this data is: 11

The median of this data is: 11

The mean and median of this data is the same in this case.
Hope this helps
Have a great day :)

3 0

2 years ago

Need help with #1 #4 #7 plz giving 15 points

valentina_108 [34]

Answer:

Q1: p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $$ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{8} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{3}$

We solve this taking LCM.

We get: $\frac{-p - 24}{3} = 3$

$\implies - p - 24 = 9$

$\implies \textbf{p} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 33}$

Q4: $\frac{\textbf{d}}{\textbf{11}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{4} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13}$

Again we proceed like Q1 by taking LCM.

We get: $\frac{d - 44}{11} = - 13$

$\implies d - 44 = - 13 \times 11 = - 143$

$\implies d = - 143 + 44$

$\implies \textbf{d} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 99}$

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$\implies 5t - 4t = - 1 - 12$

$\implies (5 -4)t = - 13$

$\implies \textbf{t} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13}$

Hence, the answer.

7 0

2 years ago

Describe the relationship between the terms in each arithmetic sequence. Then write the next three terms in each sequence.

11111nata11111 [884]

Answer:

For the first one: they increase in by 14, so the three could be 73,87,101

Second: Sequential, increasing by 20, next could be 110, 130, 150

Third: Increase by 27, next three could be 122,149,176

8 0

2 years ago

From least to greatest 2.3, 2 4/5, 2.6

algol [13]

2.3, 2.6, 2 4/5

2 4/5= 2.8

7 0

2 years ago

Gina looked at the architectural plan of a room with four walls in which the walls meet each other at right angles. The length o

Lerok [7]

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

AC is the diagonal whose length is 18.79 inches.

The length of wall AB is 17 inches.

From the given information, we have to determine the length of the BC, which is depicted a $x$ , because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.

In order to determine the length of the wall BC, or $x$ , we will have to employ the Pythagoras' Theorem here. Thus:

$x=\sqrt{(AC)^2-(AB)^2}$

$x=\sqrt{(18.79)^2-(17)^2}\approx\sqrt{64.06} \approx8$

Thus, $BC\approx 8$ inches

$\therefore AB\neq BC$ and hence, the given room is not a square.

8 0

2 years ago