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lina2011 [118]
3 years ago
12

What is the area of triangle UVW if the area of triangle RST is 36 cm and the scale

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

  225 cm²

Step-by-step explanation:

The ratio of areas is the square of the scale factor.

  area UVW = (5/2)²·area RST = (25/4)(36 cm²) = 225 cm²

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1) El largo de un rectángulo mide el triple que su ancho. Si el ancho mide 12 cm, el perímetro del rectángulo es: Selecciona la
Wittaler [7]

Answer:

1) c) 96 cm

2) c) 17,15 m

3) c) 294 m

4) d) 332 metros

Step-by-step explanation:

1)

La fórmula para el perímetro de un rectángulo = 2L + 2W

= 2 (largo + ancho)

L = longitud

W = ancho

Se nos dice en la pregunta que:

La longitud de un rectángulo es tres veces su ancho. Si el ancho es de 12 cm

Por lo tanto,

L = 3 W

L = 3 × 12

Largo = 36cm

Por lo tanto, el perímetro =

2 (largo + ancho) cm

= 2 (36 + 12) cm

= 2 (48) cm

= 96 cm

2)

La fórmula para el perímetro de un heptágono regular = 7a

Donde a = longitud de un lado

De la pregunta,

a = 2,45 m laterales

Por lo tanto, el perímetro de un Heptágono regular = 7 (2,45 m)

= 17,15 m

3)

La fórmula para el perímetro de un rectángulo = 2L + 2W

= 2 (largo + ancho)

L = longitud

W = ancho

Se nos dice en la pregunta que:

Si un campo de fútbol tiene 98 m de largo y su ancho es igual a la mitad de esta medida,

Por lo tanto,

L = 98 m

W = 1/2 de longitud

Ancho = 1/2 (98)

= 49

Por lo tanto, el perímetro =

2 (largo + ancho) m

= 2 (98 + 49) m

= 2 (147) m

= 294 m

4)

El parque es de forma rectangular.

Longitud = 45 m

Ancho = 38.000 mm

Convertir mm en m

1 milímetro = 0,001 metro

38.000 milímetro =

38.000 × 0,001 metros

= 38 metros (38 m)

La distancia alrededor del parque = perímetro del parque

Perímetro = 2 (L + W)

= 2 (45 + 38)

= 2 (83)

= 166 m

Distancia alrededor del parque una vez = 166 m

Pero nos dijeron que dio la vuelta al parque 2 veces, por lo tanto, la distancia que recorrió = 166 m × 2

= 332m

4 0
3 years ago
Use the divergence theorem to find the outward flux of the vector field F(xyz)= 4x^2 i + 4y^2 j + 3z^2 k across the boundary of
Pavel [41]

\vec F(x,y,z)=4x^2\,\vec\imath+4y^2\,\vec\jmath+3z^2\,\vec k\implies\nabla\cdot\vec F=8x+8y+6z

Let S be the surface of the rectangular prism bounded by the planes x=0, x=a, y=0, y=b, z=0, and z=c. By the divergence theorem, the integral of \vec F over S is given by the integral of \nabla\cdot\vec F over the interior of S (call it R):

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

=\displaystyle\int_0^c\int_0^b\int_0^a(8x+8y+6z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=\boxed{abc(4a+4b+3c)}

5 0
3 years ago
Find the range.<br><br>3 -9 7 -1 5 -4 2 ​
ikadub [295]

Answer: The range is 94.

Hope this helps

8 0
3 years ago
Find the distance between the following points: (0,0,0) and (-2,6,3)
marusya05 [52]

9514 1404 393

Answer:

  3.  7

Step-by-step explanation:

The distance formula applies in 3 dimensions as well as 2.

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

  d = √((-2)² +6² +3²) = √(4 +36 +9) = √49

  d = 7

The distance between the two points is 7 units.

6 0
2 years ago
Ted brought a cooler containing 7.5 liters of water to a picnic. If 500 milliliters of water are served to each person, how many
bekas [8.4K]
Answers:
k = 13The smallest zero or root is x = -10
===============================
Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
7 0
3 years ago
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