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34kurt
3 years ago
6

I Don't know any of this just started a new topic

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
To help you , divide 1/4 and that will give you 0.25. 0.25 is greater than 0.15 so put the sign eating the 1/4. (Btw this is question 4)
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Jose purchased 4/9 pound of peanut and 7/11 pounds of raisins find the total weight of his purchase
azamat

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

Total:

The least common multiple between 9 and 11 is 99.

Then

\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08

The total weight of his purchase is 1.08 pounds

8 0
3 years ago
Plzzzzz help due in a few minutes and will fail if not answered by this plzzzzzz help can not figure out!!!!!!!! Will give brain
gulaghasi [49]
You want it to be 14 by 16 tiles to recreate King Kyle’s tomb.
6 0
4 years ago
Read 2 more answers
P(x) =x and q(x) = x-1Given:minimum x and Maximum x: -9.4 and 9.4minimum y and maximum y: -6.2 and 6.2Using the rational functio
Arte-miy333 [17]

we have the following function

\frac{p(x)}{g(x)}=\frac{x}{x\text{ -1}}

where x is between -9.4 and 9.4 and y is between -6.2 and 6.2.

We will first draw the function

from the graph, we can see that the zeroes are all values of x for which the graph crosses the x -axis

In this case, we see that that the only zero is at x=0.

Now, we have that the asymptotes are lines to which the graph of the function get really close to. On one side, we can see that as x goes to infinity or minus infinity, the values of the function get really close to 1. So the graph has a horizontal asymptote at y=1. Also, we can see that as x gets really close to 1, the graph gets really close to the vertical line x=1. So the graph has a vertical asymptote at x=1.

Recall that the domain of a function is the set of values of x for which the function is defined. From our graph, we can see that graph is not defined when x=1. So the domain of the function is the set of real numbers except x=1. Now, recall that the range of the function is the set of y values of the graph. From the picture we can see that the graph has a y coordinate for every value of y except for y=1. So, this means that the range of the function is the set of real numbers except y=1.

From the graph, we can see that we cannot draw the graph having a continous drawing. That is, imagine we take a pencil and start on one point on the graph on the left side. We can draw the whole graph on the left side, but we cannot draw the graph on the right side without lifting the pencil up. As we have to "lift the pencil up" this means that the graph is not continous

Finally note that as we have a vertical asymptote at x=1 and horizontal asymptote at y=1 we have that when y is 1 or x is 1, the function y=f(x)/g(x) is undefined

5 0
1 year ago
How to write sixty nine million seventeen thousand four hundred nine
sweet-ann [11.9K]
69,017,409 is the correct answer
6 0
3 years ago
Three women, Chantel, Marissa, and Qian, enjoy running laps around a circular track. Each women runs at a constant speed. It tak
lubasha [3.4K]

It takes 150 seconds for Qian to complete the track.

Let she runs the track in the clockwise direction.

In 60 seconds, she runs \frac{60}{150} = \frac{2}{5}th of the track.

Since she meets Marissa, who is running in the opposite (counter clockwise) direction in every 60 seconds, Marissa should have completed \frac{3}{5}th of the track.

Chantel meets Marissa in every 300 seconds.

So, in 60 seconds, she advances Marissa by \frac{1}{5}th of the track.

Hence, in 300 seconds, Qian, Marissa and Chantel all meets at the starting point.

ALITER;

Marissa meets Qian in every 60 seconds.

So, Marissa and Qian meet each other in 60th, 120th, 180th, 240th and 300th second.

But, it is given that Chantel meets Marissa in every 300 seconds.

So, in 300 seconds, Qian, Marissa and Chantel meet each other.

6 0
3 years ago
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