X - 6y=18
2x-3y=9 |*-2
x -6y=18
-4x+6y=-18
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-3x=0, x=0
2x-3y=9
2*0-3y=9
-3y=9, y=-9/3, y= -3
The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.
<h3>What are the results of the arithmetic evaluations?</h3>
The arithmetic operations above can be evaluated and simplified as follows;
(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.
(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.
(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.
Read more on arithmetic evaluations;
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Answer:
<h2>In this particular case,the target population of interest to the university administration constitutes the university students.</h2>
Step-by-step explanation:
- The university administration is interested to conduct a statistical study to identify the average or mean time taken by the students to find a vacant parking spot.
- Therefore,the research topic here is the average time taken by the university students to find parking spot. The administrator collects an inconspicuous sample of 240 samples from the target population of the study,which is the overall student population of the university.
- The sample collected by the university administration is used to observe the average or mean parking time by the university students.
