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bulgar [2K]
3 years ago
8

The set of ordered pairs described in the table below can be described as which of the following?

Mathematics
1 answer:
butalik [34]3 years ago
6 0
The set of ordered pairs are both relation and function

It is a function because, for every value of x, there is one unique value of y

It is a 'relation' because there is a relation between two sets of values; set of x-values and set of y-values

A function is one example of a 'relation'. 

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What is the radius of this circle if the circumference is 18π cm? <br> 3 cm 9 cm 18 cm 36 cm
AveGali [126]

Answer:

The radius is 9 cm.

Step-by-step explanation:

The formula for calculating the circumference of a circle is

C=2\pi r

Where r is the radius and C is the circumference.

It was given in the question that; the circumference, C=18\pi cm.

We substitute this into the formula to obtain;

18\pi=2\pi r

Divide both sides by 2\pi

\frac{18\pi}{2\pi}=r

9=r

The radius is 9cm

5 0
4 years ago
Let the domain and codomain of functions f and g be the set of integers, f(x) = 2x+3, g(x) = 3x+2 What is the composition of f a
shutvik [7]

Answer:

Composition of f and g = 6x + 7

Composition of g and f = 6x + 11

Step-by-step explanation:

f(x) = 2x + 3

g(x) = 3x + 2

f(g(x)) = 2(g(x)) + 3 = 2(3x + 2) + 3 = 6x + 4 + 3 = 6x + 7

g(f(x)) = 3(f(x)) + 2 = 3(2x + 3) + 2 = 6x + 9 + 2 = 6x + 11

5 0
3 years ago
Yx(y+1) + 4x(y + 1) - 5(y + 1) factor
zheka24 [161]

( yx + 4x - 5 )( y + 1 )

.....................................

5 0
3 years ago
&gt;_&lt; I need some help pls,
34kurt

Answer: 80 = 20 + 5v

Step-by-step explanation:

This equation allows you to find out how many visits would create an even rate for both gyms.

7 0
4 years ago
SOMEONE HELP<br> Find sinD, sinE, cosD, and cosE. Write each answer as a fraction in simplest form.
Wewaii [24]

Answer:

Step-by-step explanation:

sinD = opposite/hypotenuse = 12/15 = 4/5

cosD = adjacent/ hypotenuse = 9/15 = 3/5

sinE = opposite/hypotenuse = 9/15 = 3/5

cosE = adjacent/ hypotenuse = 12/15 = 4/5

4 0
3 years ago
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