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2 years ago

What are three other ways to name? You may type or qx

1 answer:

7 0

A line can be named either using two points on the line (for example, ↔AB ) or simply by a letter, usually lowercase (for example, line m ). A line segment has two endpoints. It contains these endpoints and all the points of the line between them. You can measure the length of a segment, but not of a line.

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Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

6 0

3 years ago

Which is the simplified form of the expression (6 to the power of -2 times 6 to the power of 5) to the -3rd power?

julsineya [31]

Answer:

B. 1/6^9

Step-by-step explanation:

6^-2 = 1/6^2

1/6^2 * 6^5 = 6^5/6^2 = 6^3

6^(3 * -3) = 6^-9= 1/6^9

7 0

3 years ago

Read 2 more answers

I need the complete answer to this problem, please circle the final answer and what I should write

goblinko [34]

Answer:

$f(t) = 8400(1.0018)^{12t}$

2.22%

Step-by-step explanation:

$8400 is invested in an account earning 2.2% interest (APR), compounded monthly.

So, the value of the account after t years will be given by

$f(t) = 8400 (1 + \frac{2.2}{12 \times 100} )^{12t} = 8400(1.0018)^{12t}$ {Rounded to the four decimal places} (Answer)

Now, for t = 1 year, f(1) = $8586.67

So, the percentage of growth per year (APY) = $\frac{(8586.67 - 8400) \times 100}{8400} = 2.22$ % {Rounded to the nearest hundredth of percent} (Answer)

5 0

2 years ago

Find the area. Round to the nearest hundredth if necessary

lara31 [8.8K]

Add 16.7m 4 times that should be the correct answer if not sorry

5 0

3 years ago

The ratio of boys to girls in a class room is 5 to 7. If there are 30 boys then how many girls are there

Brums [2.3K]

Answer:

The ratio of boys to girls to 5:7

Let the number of boys be 5x

Let the number of girls be 7x

5x = 30

x = 6

Now just plug in 6 for the x in 7x

and number of girls 7 x 6 = 42

4 0

3 years ago

Read 2 more answers

What are three other ways to name? You may type or qx​

What are three other ways to name? You may type or qx