Answer:
Step-by-step explanation:
f"(x)=2
integrating
f'(x)=2x+c
f'(1)=2+c=4
c=4-2=2
f'(x)=2x+2
integrating
f(x)=2x^2/2+2x+a
f(x)=x^2+2x+a
f(2)=-2
(2)^2+2(2)+a=-2
4+4+a=-2
a=-2-8=-10
f(x)=x^2+2x-10
The Smallest possible value for (2 × a) - (a × b) if Positive integers a and b are each less than 6 is 1
<h3>What are positive integers?</h3>
Positive integers refers to whole numbers, that are greater than zero and do not include fractions or decimals. They include; 1, 2, 3, 4, 5, 6, 7, 8 etc
- Positive integers a and b are each less than 6
- Positive integers less than 6 are 1, 2, 3, 4, 5
Smallest possible value for (2 × a) - (a × b)
So, 1 is the smallest positive integer less than 6
(2 × a) - (a × b)
= (2 × 1) - (1 × 1)
= 2 - 1
= 1
Learn more about positive integers:
brainly.com/question/22813612
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Answer:
64
Step-by-step explanation:
That's about as much as you can simplify this problem.
I hope this helps! :)
Answer:
C. 647 square units
Step-by-step explanation:
To find the shaded area, subtract the area of the unshaded square from the area of the octagon.
<u>Area of the octagon</u>
where:
- n = number of sides
- l = length of one side
- a = apothem
Given:
Substitute the given values into the formula and solve for A:
<u>Area of the square</u>
<u>Area of the shaded region</u>
= area of the octagon - area of the square
= 815.88 - 169
= 646.88
= 647 square units (nearest square unit)
