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2 years ago

Could anybody help me with this please?

Mathematics

1 answer:

KengaRu [80]2 years ago

4 0

I think the opposite would be a circle because it would have any points.

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Put 19/22 into a percentage

erastova [34]

Answer:

19/22 into a percentage is 86.36%

6 0

3 years ago

Read 2 more answers

How do I know if it’s similar, congruent or neither?

Phantasy [73]

Answer:

These two triangles are congruent.

Step-by-step explanation:

You know this bc the markings on the drawing show that Angle B and Angle D are congruent. Also that AB is parallel to CD. This means that Angle BAC and Angle DCA are congruent by ALTERNATE INTERIOR ANGLES. Also, AC is congruent to itself. That makes the two triangles congruent by ANGLE-SIDE-ANGLE.

Now, you need to know that "congruent" triangles (and shapes in general) are the same size and shape. "Similar" triangles (shapes) are the same shape but not necessarily the same size.

5 0

2 years ago

If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?

Aleksandr [31]

Answer: 0.14

Step-by-step explanation:

Given: Mean : $\lambda=15\text{ per seconds}$

In minutes , Mean : $\lambda=4\text{ per minute}$

The exponential distribution function with parameter $\lambda$ is given by :-

$f(t)=\lambda e^{-\lambda t}, \text{ for }x\geq0$

The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-

$P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14$

Hence, the probability of waiting more than 30 seconds = 0.14

5 0

3 years ago

A rectangular prism has a length of 10 cm and width of 5 cm. If the volume of the prism is 250 cm3 , find the height. (Volume of

belka [17]

Height = 5cm

This is because

L=10

W=5

10 x 5 = 50

50 x ? = 250

---- ------

50 50

? = 5

The height is 5

4 0

3 years ago

Read 2 more answers

If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution

FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of $\hat{p}$ can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

np ≥ 10
nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of $\hat{p}$ as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0

2 years ago