How do i do this
t{50d {0}^{10} " alt=" \sqrt{50d {0}^{10} " align="absmiddle" class="latex-formula">
1 answer:
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Answer:
Perimeter of rectangle = ⇒ feet
Step-by-step explanation:
Given:
Length of a rectangular sand box =
Width of the box =
Perimeter of a rectangle =
where represents length of rectangle and
represents width of the rectangle.
Substituting values given for length and width.
Perimeter of sand box =
Simplifying by adding fractions:
⇒ (Adding whole numbers and fractions separately)
⇒ feet
Whole number 8 can be written as
⇒ feet
To add fractions we take LCD for the denominators 3,4,1.
LCD for 3 and 4 = 12 as its the least common multiple of 3,4,1.
Making denominators =12 by multiplying numerator an denominator with the corresponding numbers
⇒ feet
⇒ feet
Then we simply add numerators.
⇒ feet
⇒ feet
⇒ feet
⇒ feet
Writing fraction as a mixed number by dividing 218 by 12 and writing quotient as whole number and remainder as numerator with divisor as denominator.
⇒ feet
Simplifying fractions to simplest form.
⇒ feet
Perimeter =⇒ feet (Answer)
It is given in the question that
M is the MIDPOINT OF FG.
Since M is the midpoint of FG, therefore GM is half of FG. That is
Therefore
And FM is 13 too .