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horsena [70]
3 years ago
14

If the null hypothesis of an experiment is “The true mean weight of the geese is greater than 40 pounds” what is the alternate h

ypothesis?
Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

<em>The true average weight of geese is less than or equal to 40 pounds</em>

Step-by-step explanation:

The null hypothesis and the alternative hypothesis are two mutually exclusive statements or hypotheses that are made about a population. The purpose is to find out if, through a study of the data, sufficient evidence is obtained to reject one and accept another

The null hypothesis is denoted as H_0 and the alternative hypothesis as H_1

As they are two mutually exclusive statements then if

H_0: <em>"The true average weight of the geese is greater than 40 pounds"</em>

the alternative hypothesis must be the opposite of the null hypothesis

H_1: <em>"The true average weight of geese is less than or equal to 40 pounds"</em>

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3z+(-4)=-1 how would you find your answer to what is z?
Masja [62]

Answer:

z=1

Step-by-step explanation:

3z+(-4)=-1

Add 4 to each side

3z+(-4) +4=-1+4

3z = 3

Divide each side by 3

3z/3 = 3/3

z=1

5 0
3 years ago
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I have 60 coins, 30% are pennies, how many coins is not pennies
Digiron [165]
60 coins
30%=pennies
100-30=70% =not pennies
percent menas parts out of 100 so
70%=70/100=7/20=0.7
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3 years ago
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A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that
Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

P(A\cap B)=P(A).P(B)

Now, According to question , we can get that

P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}

So,

P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}

So, by using the conditional probability , which state that

P(B\mid A)=\frac{P(A\cap B)}{P(A)}

P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}


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4 years ago
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Answer: Answer is -6 :-DD

Step-by-step explanation:

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Mademuasel [1]

Answer:

5 1/4

Step-by-step explanation:

5 is the whole number so we up it aside.

Then we are left with 25/100,when we simplify that 25 into 25 is 1.

25 into 100 is 4 times.

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I hope this helps :)

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