Answer:
S(t) = 2 - 0.25*t
Step-by-step explanation:
A lake near the Arctic Circle is covered by a 2-meter-thick sheet of ice during the cold winter months.
When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate.
S(t) denote the ice sheet's thickness S ( measured in meters) as a function of time (measured in weeks).
Therefore the equation formed will be linear.
The equation will be of the form y = mx + b
Here S(t) = mt + b
Here m is the slope which is the rate at which ice is melting.
Putting t = 0
S(t) = 2
Putting t = 3,
S(t) = 1.25
Therefore, m*0 + b = 2 or, b = 2
and 3m + b = 1.25
or, 3m = 1.25 - 2 = -0.75
or, t = -0.25
Hence, function's formula = S(t) = -0.25*t + 2
i.e. S(t) = 2 - 0.25*t
