Answer:
Simplify the expressions inside parentheses ( ), brackets [ ], braces { } and fractions bars.
Evaluate all powers.
Do all multiplications and divisions from left to right.
Do all additions and subtractions from left to right.
Given:
Hexagonal pyramid
To find:
The edges of an hexagonal pyramid.
Solution:
Edges means lines which connecting to vertices.
Edges in the base of the pyramid:
AB, BC, CD, DE, EF, FA
Edges in the triangular shape of the pyramid:
AG, BG, CG, DG, EG, FG
Therefore edges of an hexagonal pyramid are:
AB, BC, CD, DE, EF, FA, AG, BG, CG, DG, EG, FG
Answer:
The radius is 3.24102 meters
Step-by-step explanation:
We are given
area of mural is 33 m^2
Since, the shape of mural is circular
Let's assume radius of circle as 'r'
so, we can use area of circle formula
now, we can set A=33
and then we can solve for r
we get
So,
The radius is 3.24102 meters
There is not a gcf because one is odd and the other even
For this case we have the following expression:
we observe that we have a polynomial of the second degree.
The constant term of the polynomial, is that coefficient that is not written accompanying a variable.
We have then that the constant term of the quadratic function is:
6
Answer:
the constant of the function is:
6