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Mariana [72]
3 years ago
11

I need help with math

Mathematics
1 answer:
Sav [38]3 years ago
8 0
I believe the answer would be only A
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Please help me! And please no scam answers
Yuri [45]

Answer:

Average rate of change: -3

Step-by-step explanation:

<u>Remember:</u>

The average rate of change of a function over an interval [a,b] is \frac{f(b)-f(a)}{b-a}

<u>Given:</u>

[a,b]=[1,7]

f(b)=f(7)

f(a)=f(1)

<u>Calculation:</u>

f(b)=f(7)=-(7)^2+5(7)+14=-49+35+14=-49+49=0

f(a)=f(1)=-(1)^2+5(1)+14=-1+5+14=4+14=18

\frac{f(b)-f(a)}{b-a}=\frac{0-18}{7-1}=\frac{-18}{6}=-3

Therefore, the average rate of change of the function g(x)=-x^2+5x+14 over the interval 1\leq x\leq7 is -3.

6 0
3 years ago
Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, squ
Anit [1.1K]
No, actually the method is not correct. Adiya needed to take x2 and subtract it from 20x. she would then get 6 = 18x. Have in mind also that she needed to divide 18. So 6 = 18x turns into 6=X. That is why is incorrect
7 0
3 years ago
Read 2 more answers
Which of these is the statement of the zero product rule?
anyanavicka [17]

Answer:

if a·b=0, then either a=0 or b=0, or both

Step-by-step explanation:

just answered it on apex :)

4 0
3 years ago
Read 2 more answers
A school has 400 students. They all come to school by bus, and each bus carries the same number of students. How many students m
Ainat [17]
Depends. All multiples of 400, you could have many different options. For example, 400 buses 1 kid on ea. 40 buses 10 kids on ea.

400x1=400
40x10=400

Just if the two numbers multiple to 400 it can be an answer
8 0
3 years ago
Read 2 more answers
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi
nalin [4]
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^{2}+(5-2)^{2}}
D=\sqrt{(4)^{2}+(3)^{2}}
D=\sqrt{16+9}
D=\sqrt{25}
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0
3 years ago
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