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3 years ago

I need help with math

Mathematics

1 answer:

Sav [38]3 years ago

8 0

I believe the answer would be only A

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Please help me! And please no scam answers

Yuri [45]

Answer:

Average rate of change: $-3$

Step-by-step explanation:

Remember:

The average rate of change of a function over an interval $[a,b]$ is $\frac{f(b)-f(a)}{b-a}$

Given:

$[a,b]=[1,7]$

$f(b)=f(7)$

$f(a)=f(1)$

Calculation:

$f(b)=f(7)=-(7)^2+5(7)+14=-49+35+14=-49+49=0$

$f(a)=f(1)=-(1)^2+5(1)+14=-1+5+14=4+14=18$

$\frac{f(b)-f(a)}{b-a}=\frac{0-18}{7-1}=\frac{-18}{6}=-3$

Therefore, the average rate of change of the function $g(x)=-x^2+5x+14$ over the interval $1\leq x\leq7$ is $-3$ .

6 0

3 years ago

Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, squ

Anit [1.1K]

No, actually the method is not correct. Adiya needed to take x2 and subtract it from 20x. she would then get 6 = 18x. Have in mind also that she needed to divide 18. So 6 = 18x turns into 6=X. That is why is incorrect

7 0

3 years ago

Read 2 more answers

Which of these is the statement of the zero product rule?

anyanavicka [17]

Answer:

if a·b=0, then either a=0 or b=0, or both

Step-by-step explanation:

just answered it on apex :)

4 0

3 years ago

Read 2 more answers

A school has 400 students. They all come to school by bus, and each bus carries the same number of students. How many students m

Ainat [17]

Depends. All multiples of 400, you could have many different options. For example, 400 buses 1 kid on ea. 40 buses 10 kids on ea.

400x1=400
40x10=400

Just if the two numbers multiple to 400 it can be an answer

8 0

3 years ago

Read 2 more answers

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi

nalin [4]

Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$
points (-3,2) and (1,5)
D= $\sqrt{(1-(-3))^{2}+(5-2)^{2}}$
D= $\sqrt{(4)^{2}+(3)^{2}}$
D= $\sqrt{16+9}$
D= $\sqrt{25}$
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle

radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0

3 years ago