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Liula [17]
3 years ago
15

Mr. Gonzales showed students part of the prime factorization of 90. One factor is missing. 2 • 32 • __

Mathematics
2 answers:
Umnica [9.8K]3 years ago
5 0

Answer:

25

Step-by-step explanatio26 = w

Elena-2011 [213]3 years ago
4 0

Answer:

25

Step-by-step explanation:cause

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seropon [69]

Answer:

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Step-by-step explanation:

6 0
4 years ago
If I'm putting £100 a month into a fund that has 13.03% annual interest annually for 48 years, what's the the total??
Katena32 [7]
I think the answer will be 35751.88
4 0
3 years ago
Consider a particle moving around a circle with a radius of 38cm. It rotates from 10 degrees to 100 degrees in 11 seconds. Calcu
kifflom [539]

Step-by-step explanation:

Given that,

Radius of circle, r = 38 cm = 0.38 m

It rotates form 10 degrees to 100 degrees in 11 seconds i.e.

\theta_i=10^{\circ}=0.174\ rad

\theta_f=100^{\circ}=1.74\ rad

Let \omega is the angular velocity of the particle such that, \omega=\dfrac{\omega_f-\omega_i}{t}

\omega=\dfrac{1.74-0.174}{11}

\omega=0.142\ rad/s

We need to find the instantaneous velocity of the particle. The relation between the angular velocity and the linear velocity is given by :

v=r\times \omega

v=0.38\times 0.142

v = 0.053 m/s

So, the instantaneous velocity of the particle is 0.053 m/s. Hence, this is the required solution.  

6 0
3 years ago
Express sin A, cos A, and tan A as ratios ​
vlabodo [156]
<h3>Answer: Choice B</h3><h3>sqrt(3)/2,    1/2,   sqrt(3)</h3>

================================================

Explanation:

Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12

Sin(angle) = opposite/hypotenuse

sin(A) = BC/AB

sin(A) = 6sqrt(3)/12

sin(A) = sqrt(3)/2

---------------

Cosine is the ratio of the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(A) = AC/AB

cos(A) = 6/12

cos(A) = 1/2

---------------

Tangent is the ratio of the opposite and adjacent

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 6sqrt(3)/6

tan(A) = sqrt(3)

5 0
3 years ago
If ∠C and ∠D are vertical angles and m ∠ C = x + 5 and m ∠ D = –2x + 80, what is m ∠ C?
amm1812

Answer:

m∠C=30°

Step-by-step explanation:

we know that

<u>Vertical Angles</u> are the angles opposite each other when two lines cross. They are always equal

so

m∠C=m∠D

substitute the given values

(x+5)\°=(-2x+80)\°

Solve for x

x+2x=80-5\\3x=75\\x=25

<em>Find the measure of angle C</em>

m∠C=(x+5)°

substitute the value of x

m∠C=(25+5)=30°

3 0
3 years ago
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