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Lorico [155]
3 years ago
11

During my three-week stay in Walla Walla, Washington, it rained for 7 days, it was sunny for 11 days, and it was overcast withou

t rain for 3 days. The next time I go to Walla Walla, I'm staying for a full leap year, or 366 days. If we assume Walla Walla will have the same ratio of rainy, sunny, and overcast days that I experienced on my last visit, how many days in my year should I expect it to rain?
Mathematics
2 answers:
Elina [12.6K]3 years ago
7 0

Answer:

122 days :D

Step-by-step explanation:

(the answer is 122.01 in a calculator, but we cant have .01 days so it rounds to 122)

Gre4nikov [31]3 years ago
4 0
Rain : sunny : overcast 
7:11:3

7x + 11x + 3x = 366
21x = 366
x = 366/21
x = 17.43

7(17.43) = 122.01 days rain
11(17.43) = 191.73 days sunny
3(17.43) = 52.29 days overcast
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Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits,
tresset_1 [31]

Answer:

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

Check for division by 3 and 6

267/3 = 89

762/6 = 127

267 is the number

3 0
3 years ago
If 5 over 6 gallon covers 1 over 4 of the house then how much paint is needed for the entire house
MissTica
If 5/6 gallons covers a quarter of the house, then you would need 4 times as much paint:
\frac{5}{6}  \times 4
Which is 20/6 gallons or 3 and 1/3 gallons
Hope this helped
4 0
3 years ago
Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars
tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
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What is the volume of a rectangular prism with the dimensions: base 7 2 cm, height 3 2 cm, and length 9 2 cm?
noname [10]

Answer:

Step-by-step explanation:

first do 72times2,32times2,92times2,  then add them all

5 0
3 years ago
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