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3 years ago

11

Xavier runs 0.75 mile each day.how far has he run at the end of 6 days

2 answers:

Bad White [126]3 years ago

4 0

I believe the answer is 4.5
Since he ran 0.75 miles each day
you can multiply .75 by 6 which gives you 4.5
HOPE THAT HELPS MERRY CHRISTMAS!!!!!

Svetllana [295]3 years ago

3 0

I think it's 4.5 miles.

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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

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3 years ago

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KATRIN_1 [288]

Answer:

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4 years ago

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Answer:

I don't know if this what you want but I will explain how I think the answer is.

Step-by-step explanation:

a) You're at positive 5, and the integer explains that you're adding negative three spaces, which just means you go back three spaces. Your spot on the number line should be 2.

b) It says to go 3 spaces back from 5. Your spot on the number line will be two.

c) You're at negative 3, and you go another 5 spaces back. Your spot on the number line will be -8.

d) You're on -3 on the number line. You remove positive 5, so your new spot on the line is -8.

e) You're at -5. You're removing positive 3. Your going back three spaces. So you would be at -8.

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4 years ago

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