Helppp pleaseee asappp

JulsSmile [24]

First, change the measurements of the pole to m so all of the units are the same.
41 cm=.41 m
72 cm=.72 m

Then, let x represent the height of the building

30/x=.72/.41
x=30*.72/.41
x=52.68 m
round to 52.7 m

6 0

3 years ago

Simplify – 2(7x – 3)

ANTONII [103]

All you need to do here is multiply the outside number by both 7x and -3.

When done correctly it should look like this:

-14x+6

Thats the answer.

7 times 2 gives you 14 but when multiplying mixed signs it turns negative so it would be -14.

negative 3 times negative 2 gives you 6. Both signs are negative, and you would suppose it would turn into a negative but thats only true when both signs are mixed. Both the 3 and the 2 are negative, making the signs the samez giving you positive

Dont forget to make this the brainliest answer to help those in need. also add a 5 star and a heart. thanks for the support hope it helped. have a nice day

5 0

3 years ago

HELP HURRY!!

Nat2105 [25]

Hmm I’m not sure what you mean by promotion. is Jane getting 23 times the amount of money she got before promotion 50?

6 0

3 years ago

The graph represents the height y, in feet, above the ground of a golf ball x seconds after it is hit.

Pachacha [2.7K]

C I think because all of them add up to it so it would be 5seconds

7 0

3 years ago

Read 2 more answers

Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability

Anna11 [10]

Answer:

a. 0.1647;
b. 0.7153;
c. 0.4453.

Step-by-step explanation:

By definition, if two event $A$ and $B$ are independent, then

$P(A\cap B) = P(A) \cdot P(B)$ . ( $P(A\cap B)$ is the probability that the outcome of both event $A$ and event $B$ are true.)

Since the outcome of these two events are independent,

$\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}$ .

The logic not operator $\lnot$ or the prime superscript $^{\prime}$ denotes that an event does not happen.

$P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39$ .

$P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73$ .

Since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}^{\prime}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that neither professor got funded:

$P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847$ .

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

$P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153$ .

Similarly, since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that Jane but not Joe got funded:

$P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453$ .

4 0

3 years ago