The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side l
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
- (1,4)
- (1,2)
- (3,2)
- (3,5)
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
===========
Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
==========
Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
- (-3,0)
- (-5,-2)
- (-1,-2)
There is no closure.
Reflection
- (3,0)
- (5,-2)
- (1,-2)
Answer:
2) D: x = [0, 24]
3) R: y = [0, 384]
4) see graph
<u>Step-by-step explanation:</u>
Eric's regular wage is $12 per hour for all hours less than 9 hours.
The minimum number of hours Eric can work each day is 0.
f(x) = 12x for 0 ≤ x < 9
Eric's overtime wage is $18 per hour for 9 hours and greater.
The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).
f(x) = 18(x - 8) + 12(8)
= 18x - 144 + 96
= 18x - 48 for 9 ≤ x ≤ 24
The daily wage where x represents the number of hours worked can be displayed in function format as follows:
2) Domain represents the x-values (number of hours Eric can work).
The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.
D: 0 ≤ x ≤ 24 → D: x = [0, 24]
3) Range represents the y-values (wage Eric will earn).
Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.
The minimum hours he can work in one day is 0.
f(x) = 12x
f(0) = 12(0)
= 0
The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>
f(x) = 18x - 48
f(24) = 18(24) - 48
= 432 - 48
= 384
D: 0 ≤ y ≤ 384 → D: x = [0, 384]
4) see graph.
Notice that there is an open dot at x = 9 for f(x) = 12x
and a closed dot at x = 9 for f(x) = 18x - 48
I hope this helped you question.... please mark as brainliest
