Answer:
CD ≠ EF
Step-by-step explanation:
Using the distance formula
d =
with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)
CD =
=
= =
Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)
EF =
=
= =
Since ≈
, then CD and EF are not congruent
Answer:
The Greatest possible value of one of the integer is 140.
Step-by-step explanation:
Given: The average (arithmetic mean) of five different positive integers is 30.
To find: What is the greatest possible value of one of these integers?
Explanation: we are given that the arithmetic mean of five positive integer
is 30.
Let the five positive integers are A,B,C,D,E
The arithmetic mean :
=30.
On multiplying both side by 5.
A+B+C+D+E =150.
The least values of A ,B,C and D can be 1 ,2,3,4.
Then : 1 +2+3+4+E =150
On simplification 10+E =150
On subtraction both side by 10 we get
E = 140 .
Therefore, the Greatest possible value of one of the integer is 140.