All categories

4 years ago

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly

Mathematics

2 answers:

I am Lyosha [343]4 years ago

8 0

Answer:

a = 6

b = 2

c = 6

d = 2

e = 6

f = 6

g=1

Step-by-step explanation:

a = 6

x^2 + 6x is equal to x(x+6)

b=2

Denominator and numerator of the first term are multiplied by x.

c=6

Second term is multiplied by (x-6)/(x-6)

d=2

Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term

e=6

In the same way as d is carried over from b, e is carried over from c.

f = 6

2x - x + 6 = x + 6

g = 1

We factor out the (x+6) from the numerator and denominator

Lina20 [59]4 years ago

4 0

A = 6
x^2 + 6x is equal to x(x+6)
b=2
Denominator and numerator of the first term are multiplied by x.
c=6
Second term is multiplied by (x-6)/(x-6)
d=2
Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term
e=6
In the same way as d is carried over from b, e is carried over from c.
f = 6
2x - x + 6 = x + 6
g = 1
We factor out the (x+6) from the numerator and denominator

You might be interested in

What is the most logicial first step in solving the equation x^2+6x+9=10

lina2011 [118]

Factor the side effects of equivalent subtract 9 from both sides of the equivalent take the square root of both sides of the equation subtract 10 from both sides of the equation

3 0

3 years ago

Which graph represents a linear function?<br>

Ymorist [56]

2nd graph (straight line)

5 0

3 years ago

Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

Variances indicate a.the cause of the variance. b.who is responsible for the variance. c.when the variance should be investigate

Nezavi [6.7K]

Option c. is the correct answer.

When the variance should be investigated.

A variance is the difference between a result's actual value and what was anticipated or budgeted. Variances can be either positive or negative. When the actual is higher than the projected or budgeted amount, a favorable variance occurs. The variance is unfavorable when actuals fall short of the amounts allocated in the budget. A variance therefore shows whether or not the actual performance is proceeding as expected.

While,

Option a. is inaccurate. As, the cause of the variance can vary, depending on factors like changes in delivery costs, market costs, production techniques, the use of subpar materials, seasonal factors, or even a simple mistake. Therefore, additional research and subsequent actions are needed to identify the cause of the variance. The cause of a variance cannot be identified by the variance itself.

Option b. is inaccurate. A variance only shows the discrepancy between the anticipated and actual amounts. It makes no mention of who is to blame for the deviation.

Option d. is inaccurate. After variances are identified, one of the most important steps is to investigate them. When actual performances significantly deviate from anticipated outcomes, variations are typically investigated.

Find more on Variance at : brainly.com/question/13287252

#SPJ4

3 0

2 years ago

Most of the heat loss for outdoor swimming pools is due to surface

fgiga [73]

Answer:

rectangle

Step-by-step explanation:

Perimeter of 20 feet

rectangle (square is technically a rectangle):

sides 5 and 5

5*5 = 25ft²

Circle:

20/(2π) = 3.18309...

3.1809...²π = 31.831ft²

Max area of rectangle (i.e. square) has a smaller area than a circle.

5 0

3 years ago