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aliya0001 [1]
3 years ago
5

Need help with this. was removed when i posted it

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
The first, third and fourth points are the answers
You might be interested in
Help please.........
Ksenya-84 [330]

Answer: 36000

Step-by-step explanation:

try looking it up lol

6 0
2 years ago
Which of the following is an example of a null hypothesis? A. The average quantity of detergent put into a box by this filling m
gavmur [86]

Answer:

C

Step-by-step explanation:

Null hypothesis: hypthesis to test that there is no significant difference between the specific characteristic of a population. Analysts look to reject a null hypothesis

A. the shipping company's average delivery time is different from 3 days. This is an example of alternative hypothesis. Null hypothesis is writtien as a claim

B. This again is an example of alternate hypthesis. The claim that mean is 0.03 is rejected with the results

C. This is a claim

D. This is rejection of a claim that mean is 1 pound

E. This is rejection of claim that average delivery time is 3 days.

5 0
3 years ago
Sam scored 59, 64, and 68 on three tests. How many points should he get on the fourth test to get an average score of 70? A. 63.
olga2289 [7]
To find this out the easy way, add up all the numbers and an answer, then divide by 4.
59 + 64 + 68 + 63.67 = 254.67
254.67/4 = 63.66
A is not correct.
59 + 64 + 68 + 65.25 = 256.25
256.25/4 = 69.25
B is not quite correct.
59 + 64 + 68 + 75 = 266.
266/4 = 66.5
C is not correct.
59 + 64 + 68 + 89 = 280
280/4 = 70.
D.) is the correct answer.
I hope this helps!
6 0
3 years ago
Read 2 more answers
15+15+15=45 7+7+7=21 4+4+4=12 4+15×7=?​
vesna_86 [32]

Answer:

109

Step-by-step explanation:

15+15+15= 45

7+7+7=21

4+4+4=12

4+15×7=109

I hope this helps!

3 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 60 o
krok68 [10]

Answer:

a) 99.7% of the widget weights lie between 45 and 75 ounces

b) 97.2% of the widget weights lie between 50 and 75 ounces

c) 84% of the widget weights lie above 55

Step-by-step explanation:

The Empirical Rule states that:

50% of the values of a measure is above the mean, and the other 50% is below the mean.

99.7% of the values of a measure lie between 3 standard deviations of the mean.

95% of the values of a measure lie between 2 standard deviations of the mean.

68% of the values of a measure lie between 1 standard deviations of the mean.

In this problem, we have that: The widget weights have a mean of 60 ounces and a standard deviation of 5 ounces.

(a) 99.7% of the widget weights lie between

3 standard deviations of the mean, so:

60 - 3*5 = 60 + 3*5 = 45 and 75 ounces

(b) What percentage of the widget weights lie between 50 and 75 ounces?

We have to find the percentage that are below 75 and subtract by the percentage that are below 50. So

75 is 3 standard deviations above the mean. So 99.7% of the measures are below 75.

50 is 2 standard deviations below the mean. So only 5% of the measures that are below the mean are below 50.

So

99.7% - (50%)5% = 99.7% - 2.5% = 97.2%

(c) What percentage of the widget weights lie above 55?

55 is one standard deviation below the mean.

50% of the widget weights are above the mean.

Of the 50% that is below, 68% lie between one standard deviation(So from 55 to 60)

So

50% + 68%(50%) = 84%

3 0
3 years ago
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