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statuscvo [17]
4 years ago
11

Really need help please

Mathematics
1 answer:
joja [24]4 years ago
6 0
The answer is A hope I help
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Solve each equation by finding all roots <br> X^4-81=0
GenaCL600 [577]
So this is a difference of 2 perfect squares
so if
x^2-y^2 then it is equal to (x-y)(x+y)

so
x^4-81=[(x^2)^2]-[(9)^2]=(x^2-9)(x^2+9)

so we know if xy=0 then x or/and y=0 so assume that they are equal to zero

x^2+9=0
we can't do anything about this because
x^2=-9
and that is not possible in the real realm


x^2-9=0
yet another difference of 2 perfect squares
x^2-3^2=(x-3)(x+3)=0
set them to zero
x-3=0
x=3
x+3=0
x=-3

so x=3 or -3
4 0
4 years ago
Read 2 more answers
For which intervals is the function increasing?
Nana76 [90]

Answer:

(-pi, 0)

Step-by-step explanation:

From the graph, we have  3 stationary point; the first one at x = 0, the second one at x = 1 and the last one at x = 2.

The function is increasing at two intervals.

The first increase is between x = -1 and x = 0.

The second increase is between x = 1 and x = 2.

From the choices give the interval that represent increase is (-pi, 0)

6 0
4 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
PLEASE HELP ANSWER THIS QUESTION
defon

#4

June is the most coldest.

How?

Mention the temperatures

  • January=+6°C
  • June=-24°C
  • November=-2°C

Lowest is the coldest .(June is the coldest month)

3 0
3 years ago
Read 2 more answers
Please help me! Im so confused, I need an answer ASAP please!!!
scoundrel [369]

Answer:

B

Step-by-step explanation:

18 x 2 = 36

20 x 2 = 40

36 + 40 = 76 miles

8 0
4 years ago
Read 2 more answers
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