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Sladkaya [172]
2 years ago
14

Let v1=(1, 6) and v2=(5, -3)

Mathematics
1 answer:
astraxan [27]2 years ago
3 0

Answer:

See Explanation;

Step-by-step explanation:

The given vectors are;

v_1=\:\: and v_2=\:\:

a) To add or subtract two vectors, we add or subtract their corresponding components

v_1+v_2=\:\:+\:\:

v_1+v_2=\:\:

v_1+v_2=\:\:

v_1-v_2=\:\:-\:\:

v_1-v_2=\:\:

v_1-v_2=\:\:

v_2-v_1=\:\:-\:\:

v_2-v_1=\:\:

v_2-v_1=\:\:

b) See attachment for graphs(1,6

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Step-by-step explanation:

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Therefore since there is <em>x</em> number of students in each of the 4 groups, there is 4 * x number of total students in all groups combined.

Since the question already indicates that there are a total of 36 students in the class, then we can indicate that..

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Answer:

Z=±1.65

Step-by-step explanation:

Some previous concepts

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The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

System of hypothesis

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The significance level provided is \alpha=0.1 and the value of \alpha/2= 0.05.

Since we are conducting a bilateral test, then we have two critical values. We need to find two quantiles that accumulates 0.05 of the area on the tails of the normal standard distribution. And in order to find it we can use the following excel codes:

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And we got this:

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Which of the following equations can be used to find the length of EF in the
Vinil7 [7]

The equation which can be used to find the length of EF is option A which is  EF=\sqrt{24^{2} -12^{2} }.

Given the length of base of right angled triangle is 12 and the hypotenuse be 24.

We are to find the length of EF and tell which equation can be used to find the length of EF.

We know that pythagoras theorem applies in a right angled triangle.

Pythagoras theorem says that in a right angled triangle the square of the hypotenuse is equal to the sum of square of base and perpendicular.

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In this triangle we are only given base and hypotenuse and we have to find EF which is perpendicular.

(DE)^{2} =(EF)^{2} +(DF)^{2}

EF=\sqrt{DE^{2}-DF^{2}  }

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=\sqrt{576-144}

=\sqrt{432}

Hence the equation which can be used to find the length of Ef is option A which is  EF=\sqrt{24^{2} -12^{2} }.

Question is incomplete as it should include the figure also.

Learn more about pythagoras theorem at brainly.com/question/343682

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