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hoa [83]
3 years ago
5

Neil has been running a tutoring business since 2005. He charges a monthly fee for weekly tutoring sessions and a phone help lin

e. Each year, he has increased his fee by the same amount. The table shows what Neil charged each customer for two given years of his business:
Year Annual Tutoring Fee
2005 $1200
2008 $1350


A. What is the rate of change and initial value for Neil’s business? How do you know?
B. Write an equation in slope-intercept form to represent the fees that Neil charges each year.
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

<u>Part A. Rate of change $ 50</u>

<u>The initial value of Neil's business is $ 1,200</u>

<u>Part B. x = 1200 + 50y</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Year Annual Tutoring Fee

2005        $ 1,200

2008        $ 1,350

2. What is the rate of change and initial value for Neil’s business? How do you know?

Rate of change = (Annual Tutoring Fee in 2008 - Annual Tutoring Fee in 2005)/(2008 - 2005)

Replacing with the values we have:

Rate of change = (1,350 - 1,200)/3

<u>Rate of change = 150/3 = $ 50</u>

<u>The initial value of Neil's business is $ 1,200</u>

3. Write an equation in slope-intercept form to represent the fees that Neil charges each year.

Let x to represent the the fees that Neil charges annually and y to represent the number of years after 2005, we have:

<u>x = 1200 + 50y</u>

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