William buys two bags of peaches and three bags of apricots for 17 dollars. Sylvia buys four bags of peaches and two bags of apr
1 answer:
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Answer:
21, 22 and 26
Step-by-step explanation:
To answer this question first we need to know which are the factors of 12:
So, now, we need 3 numbers that are <u>between 20 and 30 and that only have one common factor with 12</u>, in other words, they need to have just a 2 or a 3 in their factorization.
Let's take number 21:
, we can see that 21 only has a 3 and a prime so therefore it has only one common factor with 12
Now, let's take the number 22,
, thus since 22 has a 2 and a prime, it has only one common factor with 12.
Now, let's take the number 26
, thus, since 26 has a 2 and a prime, it has only one common factor with 12.
Thus, the three possible answers are 21, 22 and 26
Answer:
The Math Club must sell at least 50 pies to reach the goal
The graph in the attached figure
Step-by-step explanation:
Let
x-----> the number of sold pies
we know that
The inequality that represent the situation is
Solve for x
Divide by 4 both sides
The solution is the interval ------> [50,∞)
All positive whole numbers greater than or equal to 50
In a number line the solution is the shaded area at right of x=50 (close circle)
The Math Club must sell at least 50 pies to reach the goal
using a graphing tool
see the attached figure
