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Pavel [41]
3 years ago
11

How to draw x is less than and equal to 11/5 on number line?

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0
First, write out the statement as an inequality so that it looks like this: x<span>≤11/5
Then you graph it on a number line, and since you know anything greater/less than or equal to is a closed circle since it includes the value 11/5, you would plot a closed circle on 11/5 on a number line and draw and arrow pointing towards the left to show that only values 11/5 or under can satisfy x.


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Please help me with this!!
Troyanec [42]

Answer:

As the height increases, the temperature decreases.

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At the height 8 km the temperature is 0°.

5 0
3 years ago
If you apply ghe change below to the quadratic parent function f(x)=x2 what is the equation of the new function? Shift 1 unit ri
saveliy_v [14]

1 to left gives (x -1)^2

vertical stretch makes it 5(x - 1)^2

reflection in axis changes the sign to - :-

equation of new function is f(x) = -5(x - 1)^2

6 0
3 years ago
Which figure has one line of symmetry but no rotational symmetry?
Slav-nsk [51]
C because u can split it only once vertically but it’s not a rotationally symmetrical shape
6 0
3 years ago
pleaseee help context is down below $3 is the entrance fee while $.50 is for each game played that's enough evidence to solve C(
BabaBlast [244]
C= Cost
g= # of times games played

C = 0.50g + 3

C(0) = 0.50(0) + 3
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5 0
2 years ago
Read 2 more answers
Please help me!!! i will gladly give brainliest :)
True [87]

Given:

ΔONP and ΔMNL.

To find:

The method and additional information that will prove ΔONP and ΔMNL similar by the AA similarity postulate?

Solution:

According to AA similarity postulate, two triangles are similar if their two corresponding angles are congruent.

In ΔONP and ΔMNL,

\angle ONP\cong \angle MNL       (Vertically opposite angles)

To prove ΔONP and ΔMNL similar by the AA similarity postulate, we need one more pair of corresponding congruent angles.

Using a rigid transformation, we can prove

\angle NOP\cong \angle NML

Since two corresponding angles are congruent in ΔONP and ΔMNL, therefore,

\Delta ONP\sim \Delta MNL        (AA postulate)

Therefore, the correct option is A.

8 0
3 years ago
Read 2 more answers
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