The answer is C(-2, 6).
I think you forgot the y in the first equation (with the -4.
Thank would be 3/4 or .75 or 75%
S(x) = x - 7; t(x) = 4x² - x + 3
(t · s)(x) = (4x² - x + 3)(x - 7) = (4x²)(x) + (4x²)(-7) - (x)(x) - (x)(-7) + (3)(x) + (3)(-7)
= 4x³ - 28x² - x² + 7x + 3x - 21 = 4x³ - 29x² + 10x - 21
Step-by-step explanation:
the distance of a vertex on the 2 outgoing sides to the touching points with the inscribed circle is the same for both sides.
and that applies to all 3 vertexes.
so, we know for the top left vertex the distance to both touching points is 4.
that means the distance to the touching points from the bottom left vertex is 7-4 = 3.
and that means that the distance to the touching points from the bottom right vertex is 16-3 = 13.
so, x = 13
it is the distance to one of the touching points for the bottom right vertex.
and the perimeter of the triangle is therefore
7 + 16 + (13 + 4) = 40
Answer:
5 + 5 = 10
Step-by-step explanation:
If you know that 5 + 5 = 10, you can solve 5 + 6 = 11. You are adding one more to the addends (adding 6 instead of adding 5), so you add one more to the sum (11 instead of 10).
