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3 years ago

9

Which of the following was the primary difference between newspapers in ancient Rome and ancient China? Roman newspapers were pr

inted. Roman newspapers included only sports news. Chinese newspapers were printed. Chinese newspapers recorded only political news.

1 answer:

egoroff_w [7]3 years ago

4 0

Answer:

I believe the answer is:

. Rome newspapers were printed.

Hope this helps!!!

Explanation:

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The factor of 2ax^2+4axy+3bx^2+2ay^2+6bxy^+3by^2

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Answer:

$2ax^2+4axy+3bx^2+2ay^2+6bxy+3by^2= (x+y)^2(2a+3b)$

Explanation:

Given

$2ax^2+4axy+3bx^2+2ay^2+6bxy+3by^2$

Required

Factorize

$2ax^2+4axy+3bx^2+2ay^2+6bxy+3by^2$

Rewrite as:

$2ax^2+4axy+2ay^2+3bx^2+6bxy+3by^2$

Use square parenthesis

$[2ax^2+4axy+2ay^2]+[3bx^2+6bxy+3by^2]$

Expand each bracket

$[2ax^2+2axy+2axy+2ay^2]+[3bx^2+3bxy+3bxy+3by^2]$

Factorize each:

$[2ax(x+y) + 2ay(x+y)]+[3bx(x+y)+3by(x+y)]$

$[(2ax+2ay)(x+y)]+[(3bx+3by)(x+y)]$

Further, factorize:

$(x+y)[(2ax+2ay)]+[(3bx+3by)]$

$(x+y)[(2ax+2ay)+(3bx+3by)]$

Remove bracket

$(x+y)[2ax+2ay+3bx+3by]$

Reorder:

$(x+y)[2ax+3bx+2ay+3by]$

Factorize:

$(x+y)[x(2a+3b)+y(2a+3b)]$

$(x+y)[(x+y)(2a+3b)]$

Remove square bracket

$(x+y)(x+y)(2a+3b)$

This gives:

$(x+y)^2(2a+3b)$

Hence:

$2ax^2+4axy+3bx^2+2ay^2+6bxy+3by^2= (x+y)^2(2a+3b)$

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