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ioda
3 years ago
14

Factor 3/4 out of 3/4z + 6

Mathematics
2 answers:
posledela3 years ago
7 0
<span>we will do factor 3/4 out of 3/4z + 6

we have 3/4 z+6= 3/4 z+ 3/4x8= 3/4(z+8)

we have done
Have a good day</span>
Alenkasestr [34]3 years ago
5 0
ANSWER

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


EXPLANATION

We want to factor
\frac{3}{4}
out of

\frac{3}{4} z + 6

The first term is already having a factor of
\frac{3}{4}
The constant term which is the second term is not having a factor of
\frac{3}{4}
so we need to use a trick of multiplying and dividing by the same factor to obtain,



\frac{3}{4} z + 6 =  \frac{3}{4} z +  \frac{3}{4}  \times  \frac{6}{ \frac{3}{4} }


We can now factor
\frac{3}{4}
out of the right hand side to obtain,

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  \frac{6}{ \frac{3}{4} } )
Let us rewrite the right most fraction using the normal division symbol.

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  6 \div  \frac{3}{4}  )




We simplify to obtain,

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  6  \times  \frac{4}{3}  )



This further gives us,


\frac{3}{4} z + 6 =  \frac{3}{4} (z +  2 \times  4  )



\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


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Answer:

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Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where the variables are the respective points of B and C,

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Plugging into the formula we get:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}

Summing it all (perimeter is sum of 3 sides):

Distance = 4+5+\sqrt{41}\\ =9+\sqrt{41}

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3 years ago
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