All categories

3 years ago

which property of equality is used to arrive at the conclusion for the following: If x = 4, then x + 12 = 16

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Algebra is the answer

Kitty [74]3 years ago

4 0

I believe it's the addition property of equality

You might be interested in

Aralynn is making a quilt. She has used 5.5 balls of yarn and will need 8

miskamm [114]

Answer:

13.5

Step-by-step explanation:

5.5+8=13.5

4 0

3 years ago

on a map, two cities measure 6.2 cm apart. If the scale of the map is 5 cm per 10 miles, then how many miles apart are the citie

miss Akunina [59]

The cities are 12.2 miles apart

<u>Step-by-step explanation:</u>

The scale of the map is,

5cm = 10 miles

The distance between the 2 cities in map is 6.2 cm

The actual distance between the 2 cities = (6.2 x 10) / 5

= 62/5

= 12.4

The 2 cities are 12.4 miles apart.

8 0

3 years ago

Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

6 0

3 years ago

Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po

Brrunno [24]

Answer: (0.63, 7.07)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

Given : $\hat{p} =0.7$ ; $n=110$

Significance level : $1-0.90=0.1$

Critical value : $z_{\alpha/2}=1.645$

Now, a 90% confidence interval for population proportion will be :-

$0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{110}}\\\\\approx0.7\pm0.07\\\\=(0.7-0.07,0.7+0.07)=(0.63,\ 7.07)$

Hence, a 90% confidence interval for population proportion = (0.63, 7.07)

5 0

3 years ago

One advantage of credit-card buying is the monthly list of expenditures you receive. True or False

Elenna [48]

False

it is false because the funds will not last forever, you will run out of money

7 0

3 years ago

Read 2 more answers