Question

Victor drew trapezoid PQRS on a coordinate plane p(7,4) q(10,4) r(13,-1) s(8,-1) what is length in units of side ps

Answer 1

Answer:

PS=$\sqrt{26}units$

Step-by-step explanation:

Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).

To find:: Length of the side PS

Solution : Using the distance formula, we can find the length of the side PS, therefore

PS=$\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2}$

PS=$\sqrt{(-1-4)^{2}+(8-7)^2 }$

PS=$\sqrt{(-5)^2+(1)^2}$

PS=$\sqrt{25+1}$

PS=$\sqrt{26}units$

which is the required length of the side PS.