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3 years ago

How much lighter is 345 g than 1,1 kg

Mathematics

1 answer:

NemiM [27]3 years ago

3 0

Answer:

755 gram lighter

Step-by-step explanation:

Convert 1.1kg into gram by multiplying it with 1000

1.1 x 1000= 1100 and we take this amount and subtract it with 345g

1100-345= 755g

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S f(-x)= x^2 -1 odd, even or neither

natka813 [3]

Answer:

f(x) = f(-x) = x^2 -1 is an even function

Step-by-step explanation:

When f(x) = f(-x), the function is symmetrical about the y-axis. That is the definition of an even function.

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An odd function is symmetrical about the origin: f(x) = -f(-x).

5 0

3 years ago

I need an answer right now

amm1812

Answer:

Step-by-step explanation:

(1x/4 + 1/7) + (3x/8 - 1/3) = x/4 + 3x/8 + 1/7 - 1/3

= x*2/4*2 + 3x/8 + 1*3/7*3 - 1*7/3*7

= 2x/8 + 3x/8 + 3/21 - 7/21

= (2x+3x)/8 + (3-7) /21

= 5x/8 + (-4)/21

= 5x/8 - 4/21

8 0

3 years ago

Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3

s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $\frac{((a^2)^{-2})^5}{a^4.a^3}$

We know that when the bases are same the powers can be added. i.,e.,

(xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $\frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7}$

$\implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27}$

Also, $\frac{x^a}{x^b} = x^{a - b}$

This is nothing but, $\frac{1}{a^{27}}$ .

Note that $a$ cannot be zero here. The condition is provided in the question as well.

7 0

3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

Read 2 more answers

Costs $17.60 for a pack of 4 padlocks.Find the unit price in dollars per padlock.If necessary, round your answer to the nearest

mel-nik [20]

4=$17.60

1=$17.60/4

1=$4.40

Hole this helps :)

6 0

3 years ago

How much lighter is 345 g than 1,1 kg​

How much lighter is 345 g than 1,1 kg