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3 years ago

13

Which number is prime A 15 B 23 C 45 D 51

1 answer:

777dan777 [17]3 years ago

7 0

Is prime(23) = True------------------

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Sorry really bad with fractions!! Help

earnstyle [38]

X/4 + 1 = -6
x/4 = -6 -1
x/4 = -7
x= -28

3 0

2 years ago

Read 2 more answers

What is the answer for this too?

Vikki [24]

The answers once compounded equals $65068.44. Hope this helps:)

8 0

3 years ago

2^3 times 2^3+= <br> what does this eqaul

VLD [36.1K]

Answer:

36

Step-by-step explanation:

2x3 x 2x3 = 36

Sorry if this didnt help

3 0

2 years ago

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Alex, Ian, and Ric together sold 48 tickets for the school fund-raiser. Alex sold 11 tickets and Ian sold 18 tickets. How many t

eimsori [14]

To determine the number of tickets that Ric sold, subtract from the total tickets sold the sum of the number of tickets sold by Alex and Ian. This is mathematically shown as,

tickets (Ric) = tickets (total) - (tickets (Alex) + tickets (Ian))

tickets (Ric) = 48 - (11 + 18) = 19

Hence, Ric sold 19 tickets for the fundraising.

8 0

3 years ago

Read 2 more answers

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago