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levacccp [35]
3 years ago
8

The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point

Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be (h,k)

Another way of representing a quadratic is in "vertex form":

f(x) = a(x-h)^2+k

Now all you have to do is solve for a.  You know that the vertex is (0,2) and you have know the point of (1,8).  Now, all you have to do is plug in these values and solve for a.

8 = a(1-0)^2+2\\8=a(1)^2+2\\8=a+2\\a=6

Now you know the equation is f(x) = 6(x-0)^2+2 , but you need it in quadratic form.  All you have to do is solve is distribute the 6:

6x^2+2

You get:

a = 6

b = 0

c = 2

Please mark this as brainliest if it satisfies your question

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NEED HELP IN FINDING AREA
Aliun [14]

Answer:

809 km²

Step-by-step explanation:

I can split this into 3 rectangles. One is 25 by 17, another is 24 by 13, and the last one is 6 by 12. (I had gotten 13 for the second rectangle because 25 - 12 = 13.)

(25 * 17) + (24 * 13) + (6 * 12) <em>{17 is the first number after a multiple of 4 (16). As a result, 25 by 17 will end in "25." 25 by 17 is 425.}</em>

425 + (24 * 13) + (6 * 12) <em>{24 by 13 is 312.}</em>

425 + 312 + (6 * 12) <em>{6 by 12 is 72.}</em>

425 + 312 + 72 <em>{From left to right, add 425, 312, and 72 to get 809}</em>

737 + 72

809 km²

The area of this figure is 809 km².

5 0
3 years ago
A line passes through the points (2,4) and (5,6) .
Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points (x_1,y_1) and (x_2, y_2)

then the general form y -y_1=m(x-x_1) for linear equations where m is the slope given by:

m =\frac{y_2-y_1}{x_2-x_1}

First calculate slope for the points (2, 4) and (5, 6);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}

then, by point slope intercept form;

y-4=\frac{2}{3}(x-2)

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}

then, by point slope intercept form;

y-6=\frac{2}{3}(x-5)

Yes, the only equation of line from the given options  which describes the given line are;

y-4=\frac{2}{3}(x-2)  and y-6=\frac{2}{3}(x-5)



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