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adoni [48]
3 years ago
15

What is 2x^2y^3/-8xy^4

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0
\dfrac{2x^2y^3}{-8xy^4}=-\dfrac{2}{8}\cdot\dfrac{x^2}{x}\cdot\dfrac{y^3}{y^4}=-\dfrac{1}{4}\cdot\dfrac{x}{1}\cdot\dfrac{1}{y}=\boxed{-\frac{x}{4y}}
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Step-by-step explanation:

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8 0
2 years ago
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Vedmedyk [2.9K]

Answer:

Answer is option b)

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

a \: walking \: path \: is \: represented \: by \:  \\ y =  - 4x - 6 \\ 4x + y + 6 = 0 \\ given \: that \\ a \: new \: path \: will \: be \: built \: perpendicular  \\ \: to \:  \: the \: walking \: path \\ the \: equation \: of \: the \: line \: perpendicular \: to \\ 4x + y + 6 = 0 \: is \\ x - 4y + k = 0 \\ since \: it \: passes \: through \: ( - 4,10) \\ substitute \: x \:  =  - 4\: and \: y = 10 \: in \: required \: equation \\  - 4 - 4(10) + k = 0 \\ k = 44 \\ then \: the \: equation \: is \\ x - 4y + 44 = 0 \\ adding \: 4y \: on \: both \: sides \\ x + 44 = 4y \\ dividing \: by \: 4 \: on \: both \: sides \\ y =  \frac{x}{4}  + 11 \\ y =  \frac{1}{4} x + 11 \\ so \: the \: answer \: is \: option \: b) \:   \frac{1}{4} x + 11

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

8 0
3 years ago
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PLEASE HELP ME IN MATH ITS URGENT
Alika [10]

Answer:

D

Step-by-step explanation:

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2 years ago
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