4 years ago

What is 2x^2y^3/-8xy^4

1 answer:

6 0

$\dfrac{2x^2y^3}{-8xy^4}=-\dfrac{2}{8}\cdot\dfrac{x^2}{x}\cdot\dfrac{y^3}{y^4}=-\dfrac{1}{4}\cdot\dfrac{x}{1}\cdot\dfrac{1}{y}=\boxed{-\frac{x}{4y}}$

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