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ASHA 777 [7]
2 years ago
8

What is the image of Q for a dilation with the center (0,0) and a scale factor of 0.5?

Mathematics
1 answer:
Lina20 [59]2 years ago
7 0

Answer: OPTION A.

Step-by-step explanation:

A dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape, but they have different sizes.

In this case you know that the dilation is centered at the origin and the scale factor is:

k=0.5

Therefore, the rule is the following:

Q(kx,ky)

You can identify in the figure attached that the point Q is:

Q(1,5)

Therefore, you must multiply its coordinates by the scale factor 0.5 in order to get its Image Q'. This is:

Q'=(1*0.5,5*0.5)\\\\Q'=(0.5.2.5)

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Refer to the figure to answer the question.
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Answer:

It's HG

Step-by-step explanation:

The line of intersection is where they cross, and this line is the line HG

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The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.
pickupchik [31]

Answer: first option.

Step-by-step explanation:

The ratio of the area of the triangles can be calculated as following:

ratio_{(area)}=(\frac{l_1}{l_2})^2

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}

It can be written as following:

ratio_{(area)}=49:64

The ratio of the perimeter is:

ratio_{(perimeter)}=\frac{l_1}{l_2}

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}

It can be written as following:

ratio_{(perimeter)}=7:8

5 0
3 years ago
A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested
Xelga [282]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1

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3 years ago
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