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Murljashka [212]
3 years ago
7

2.8 Code Practice: Question 1

Computers and Technology
2 answers:
likoan [24]3 years ago
6 0

Input: A = 2, B = 8, C = 1

Output: Largest number = 8

-BARSIC- [3]3 years ago
4 0

Answer:

The program to this question can be given as:

Program:

#include <stdio.h> //define header file

int main() //define main method.

{

int a1,b1,c1; //define variable

printf("Enter three numbers:\n"); //message

scanf("%d",&a1); //input numbers.

scanf("%d",&b1);//input numbers.

scanf("%d",&c1);//input numbers.

if (a1>b1) //check condition

{

//check condition

if(a1>c1)//inner if block

{

printf("The largest number: %d", a1); //message

}

else  //inner else block

{

printf("The largest number: %d", c1);//message

}

}

else //else block

{

//check condition

if(b1>c1) //inner if block.

{

printf("The largest number: %d", b1);//message

}

else //else block

{

printf("The largest number: %d",c1);//message

}

}

return 0;  //return 0.

}

Output:

Enter three numbers:

22

44

11

The largest number: 44

Explanation:

The description of the above program can be given as:

  • In the C language program firstly we define the header file. Then we define the main function. In the main function, we define three variables that are "a1, b1 and c1". In this variable, we take input from the user.
  • Then we define the conditional statements. In the if block we check if the value of a1 is greater then the value of b1 if this condition is true so we use another condition that if the value of a1 is greater then the value of c1. so, it will print the largest value. If the above condition is not true then it will go to else section.
  • In the else part we check the condition that if the value of b1 is greater then the value of c1. if it is true it will print the largest number value.  
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4 years ago
Description:
Nastasia [14]

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

<em>int convert(float miles) </em>

<em>{ </em>

<em>    return miles * 5280; </em>

<em>} </em>

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

<em>    while(response == 'y') </em>

<em>    { </em>

<em>    cout<<"How many miles did you walk?. "; </em>

<em>    cin>>miles; </em>

<em>    cout<<"You walked "<<convert(miles)<<" feet"<<endl; </em>

<em>    cout<<"Continue? (y/n): "; </em>

<em>    cin>>response; </em>

<em>    } </em>

   cout<<"Bye!";

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