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juin [17]
3 years ago
7

What are the two most popular applications of theInternet?

Computers and Technology
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

1) Electronic mailing

2) Web browsing

Explanation:

Electronic mail: For hundreds of millions of individuals, e-mail has become an significant component of private communications, many of whom have substituted it with letters or phone calls. E-mail has become an significant advertising medium in company, especially in cases where time-sensitive demand for products and services.Tickets for an upcoming sporting event, for instance, are sold by sending fans an e-mail message with ticket availability data and prices.

Web browsing: The web browsing is another critically important Internet application. The world of internet is filled with the immense of knowledge, subjects, and solutions. The user browse the internet to look out for the related queries, researches and lot other things.

You might be interested in
Which setting on a profile makes a tab NOT accessible in the All App Launcher or visible in any app, but still allows a user to
Levart [38]

Answer:

freezer

Explanation:

you can freeze your application and it won't show on your launcher till you unfreeze it

5 0
3 years ago
A certain string-processing language offers a primitive operation which splits a string into two pieces. Since this operation in
Nostrana [21]

Answer:

Explanation:

First we define define cost(i,j) to be the cost of cutting the string from index i to j. Then,

cost(i,j) = min {length of substring + cost(i,k) + cost(k,j) where i < k < j}

void  s_cut()    

 {

   int l,p;

   int temp=0;

   //ArrayList<Integer> al = new ArrayList<Integer>();

   int al[];

   Scanner s=new Scanner(System.in);

   int table[][];

   ArrayList<Integer> values[][];

   int low=0,high=0;

   int min=0;

   l=s.nextInt();

   p=s.nextInt();

   System.out.println("The values are "+l+"  "+p);

   table= new int[l+1][l+1];

   values= new ArrayList[l+1][l+1];

   al= new int[p];

   for(int i=0;i<p;i++)

   {

       al[i]=s.nextInt();

   }

   for(int i=0;i<=l;i++)

   for(int j=0;j<=l;j++)

       values[i][j]=new ArrayList<Integer>();

   System.out.println();

   for(int i=1;i<=l;i++)

       table[i][i]=0;

   //Arrays.s

   Arrays.sort(al);

   for(int i=0;i<p;i++)

   {

       System.out.print(al[i]+ "  ");

   }

   for(int len=2;len<=l;len++)

   {

       //System.out.println("The length is  "+len);

       for(int i=1,j=i+len-1;j<=l;i++,j++)

       {

           high= min_index(al,j-1);

           low= max_index(al,i);

           System.out.println("Indices are "+low+"  "+high);

           if(low<=high && low!=-1 && high!=-1)

           {

           int cost=Integer.MAX_VALUE;;

           for(int k=low;k<=high;k++)

           {

               //if(al[k]!=j)

               temp=cost;

               cost=Math.min(cost, table[i][al[k]]+table[al[k]+1][j]);

               if(temp!=cost)

               {

                   min=k;  

                   //values[i][j].add(al[k]);

                   //values[i][j].addAll(values[i][al[k]]);

                   //values[i][j].addAll(values[al[k]+1][j]);

                   //values[i][j].addAll(values[i][al[k]]);

               }

               //else

               //cost=0;

           }

           table[i][j]= len+cost;

           values[i][j].add(al[min]);

           //values[i][j].addAll(values[i][al[min]]);

           values[i][j].addAll(values[al[min]+1][j]);

           values[i][j].addAll(values[i][al[min]]);

           }

           else

               table[i][j]=0;

           System.out.println(" values are "+i+"  "+j+"  "+table[i][j]);

       }

   }

   System.out.println(" The minimum cost is "+table[1][l]);

   //temp=values[1][l];

   for(int e: values[1][l])

   {

       System.out.print(e+"-->");

   }

8 0
4 years ago
A company has a main office and 12 branch offices. The users and computers are within a single domain. All servers are Windows S
LenaWriter [7]

Answer:

The answer to this question can be given as:

To access the server, the administrator must Configure L2TP with IPsec and MS-CHAPv2.

Explanation:

In this question, the user doesn't access the server by the User name and password. The User wants to access the server by the computer-level authentication. To access the server successfully user must Configure L2TP with IPsec and MS-CHAPv2. where L2TP with IPsec stands for Layer 2 Tunneling Protocol or it is also known as Virtual private network. It is a communications protocol that allows us to move data from one network to another in the encrypted form that is used by the IPsec. MS-CHAPv2 stands for Microsoft Challenge-Handshake Authentication Protocol that is developed by Microsoft. In computing, the CHAP provides the authentication to the user or network host entity. For example, this entity may be an internet service provider. And v2 stands for security.

So to access the server successfully, the administrator must Configure L2TP with IPsec and MS-CHAPv2.

8 0
3 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
A computer that connects to a powerful computer on a network is called a ______. boss client kid server
Luba_88 [7]
Server is the answer i believe.

4 0
3 years ago
Read 2 more answers
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