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ivann1987 [24]
3 years ago
11

The 6 consecutive integers is 393 what is the third number in this sequence

Mathematics
1 answer:
MAXImum [283]3 years ago
3 0
X+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=393
6x+15=393
6x=393-15
6x=378
x=63
third one is 63+2=65
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∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2

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