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san4es73 [151]
3 years ago
12

Ellen has property whose boundary lines form a triangle, as shown in the diagram. Her house lies at Vertex A and she is going to

put a bunkhouse for the ranch hands somewhere along segment BC. She wants the placement to be such that CA/CD=B/A. What must be true about segment AD so that the proportion CA/CD=BA/BD holds

Mathematics
1 answer:
baherus [9]3 years ago
6 0

Given that in a ΔABC, Ellen house lies at vertex A and bunkhouse is put somewhere along BC, let it be D.

Please refer the diagram attached.

We are also given that D must be placed such that \frac{CA}{CD}= \frac{BA}{BD} holds true.

Let us re write the above equation such that CD and BD lie on one side.

That is \frac{CA}{BA}= \frac{CD}{BD}

Which is nothing but angle bisector theorem.

Hence AD must bisect the angle A then only the given condition will hold true.

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