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Rus_ich [418]
3 years ago
12

AB = 2x-5 BC = 6x AC = 27

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

correct answer is x = 2.75

Step-by-step explanation:

Given;

AB = 2x-5

BC = 6x

AC = 27

Hence,

=> AC = AB + BC

=> 27 = 2x-5 + 6x

=> 27 = 8x-5

=> 27-5 = 8x

=> 22 = 8x

=> 22/8 = x

=> 11/4 = x

or

2.75 = x

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Please help with this math problem! Will give brainliest! :)
tangare [24]

Answer:

9

Step-by-step explanation:

All triangles (3 sided polygons) have angles added up to 180, so we can do the following:

(7x-1) + (7x+8) + (5x+2) = 180° <em>- equation</em>

7x-1 + 7x+8 + 5x+2 = 180° <em>- "distribute"</em>

19x - 1 + 8 + 2 = 180°<em> - combine the x terms</em>

19x + 9 = 180° <em>- combine the integer terms</em>

19x = 171 <em>- subtract 9 form both sides</em>

x = 9 <em>- divide both sides by 19</em>

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2 years ago
The booster club now raises $0.41 for each pom pom they sell.
VLD [36.1K]
If you do .41x122 you get 50
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Read 2 more answers
In a random sample of 18 families, the average weekly food expense was $95.60 with a sample standard deviation of $22.50. Determ
shepuryov [24]

Answer:

t-distribution should be used to construct a confidence interval.

Step-by-step explanation:

We are given that a random sample of 18 families, the average weekly food expense was $95.60 with a sample standard deviation of $22.50.

We have to determine whether a normal distribution (Z values) or a t- distribution should be used or whether neither of these can be used to construct a confidence interval.

<em><u>Since in this question we are provided with;</u></em>

Sample average weekly food expense, \bar X = $95.60

Sample standard deviation, s = $22.50

Sample of families, n = 18

The distribution that we will use here to construct a confidence interval will be <u>t-distribution</u> because in the question we don't know anything about population standard deviation (\sigma) .

Normal distribution is used when we know population standard deviation (\sigma).

So, the pivotal quantity for confidence interval that will be used is One-sample t-test statistics;

                P.Q. = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

Therefore, t-distribution should be used to construct a confidence interval.

3 0
3 years ago
Someone please helpp
umka2103 [35]

Answer:

The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.

Step-by-step explanation:

2(5m−4)−3(m−5)2=−3m2+40m−83

Add 3m^2 to both sides.

−3m2+40m−83+3m2=−3m2+40m−83+3m2

40m−83=40m−83

Subtract 40m from both sides.

40m−83−40m=40m−83−40m

−83=−83

−83+83=−83+83

0=0

If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.

6 0
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2x divided by x+5 less than or equal to 0
coldgirl [10]
It is more than 0, because you cancel the x, and you get 2+5, which is 7
4 0
3 years ago
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