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Neporo4naja [7]
3 years ago
12

Please come in clutch and help me please and thank you!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

3/20

Step-by-step explanation:

its 3/20 because its really the only possible answer that has 20 has its denominator

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Adam sleeps for nine hours each night, five nights a week, and 11 hours for two nights a week.
melisa1 [442]

Answer:

E

Step-by-step explanation:

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3 years ago
HELPP plz I need the answer with step by step don't send a file plz
svp [43]

Answer:

I uploaded a file hosting link for your question!

Here is the link:

bît.ly/endbotvirusesonbrainly

Step-by-step explanation:

B is the only set of numbers that is ordered from least to greatest.

Hope it helps :)

5 0
2 years ago
Read 2 more answers
Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer:  {x = 1/2, y = 1/3

7 0
3 years ago
What is the product of -9(5-2x)
nata0808 [166]
-45+18x is the answer
Hope this helped <3
5 0
3 years ago
Read 2 more answers
A coin is tossed 600times with the frequencies as:
brilliants [131]

Answer:

  • see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

let  \: E_1  \: and  \: E_2  \: be  \: the  \: events \:  of \:  getting  \: a  \: head

and of getting a tail respectively.

then,

1)  \: P \:  (getting \:  a  \: head) = \: P \:  (E_1)

\longrightarrow \:  \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{342}{600}  =  \frac{57}{100}

\longrightarrow \: 0.57

\red{ \rule{150pt}{3pt}} \:

2) P (getting \: a\: tail) =P (E_2)

\longrightarrow \:  \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{258}{600}  =  \frac{43}{100}

\longrightarrow \: 0.43

6 0
2 years ago
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