Answer
c,116°
Step-by-step explanation:
i don't know how to draw a diagram?
Join ends of chord with the center making angles ∠2,∠3 and angle at the center.
angle at the center=128°
∠1=∠2+90°
∠2=∠3
∠2+∠3+128=180
∠2+∠2+128=180
2∠2=180-128=52
∠2=52/2=26
∠1=26+90=116°
sorry i can't explain properly without picure.
Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
I believe the answer to be 60000 mg
Answer:
m<1 = 51
m<2 = 61
m<3 = 29
Step-by-step explanation:
three angles of a triangle = 180
so knowing that add 68 + 61 to get 129
now subtract cause the last angle will = 180-129 = 51
for angle two is 61 cause their congruent
now we have one angle = 90 and another 61
add them 90+61= 151
now subtract 180-151 = 29