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expeople1 [14]
4 years ago
14

Which has the fastest wave speed, a high frequency sound or a low frequency sound?

Physics
1 answer:
Naddika [18.5K]4 years ago
3 0

Answer:

high frequent sound

Explanation:

because if its low than its slower.

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The photoelectric effect proved:
Jobisdone [24]

Answer:

i think c)light has a charge

6 0
3 years ago
1
ehidna [41]

Answer:

a = -1.6\ m/s^2

Explanation:

<u>Accelerated Motion</u>

It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.

The acceleration is calculated as follows:

\displaystyle a=\frac{v_f-v_o}{t}

The aeroplane starts with a speed of vo=62 m/s and reaches a speed of vf=6 m/s in t=35 s.

The acceleration is:

\displaystyle a=\frac{6-62}{35}=-\frac{56}{35}

\mathbf{a = -1.6\ m/s^2}

3 0
3 years ago
Describe why wearing a long-sleeved white T-shirt can help you feel cooler on a hot day than wearing a short-sleeved black T-shi
MAVERICK [17]

Answer:

Explanation:

In a white T-shirt its is not as dark of a color as black so when the sun hits it you won't get hot as much or as quick. If you wear a back shirt you will most likely be hotter because since it is a darker color when the sun hits it it make you hotter and you heat up quicker. You still might feel hot in a white T-shirt because long sleeve shirts trap in your body heat making you hotter because the heat has nowhere else to go.

3 0
3 years ago
I need help figuring out the science question!!
Aleonysh [2.5K]

Answer:

Explanation:

Speed is the distance covered over the time taken to do so.

s = d/t = 45 m / 3 s = 15 m/s

6 0
3 years ago
Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t
marshall27 [118]

Answer:

        x = 240 m

Explanation:

This is a kinematics exercise

Let's fix our frame of reference on car A

           x = x₀ₐ+ v₀ₐ t + ½ aₐ t²

         

the initial position of car a is zero

           x = 0 + v₀ₐ t + ½ 0.8 t²

for car B

          x = x_{ob} + v_{ob} t - ½ a_b t²

     

car B's starting position is 30 m

         x = 30 + v_{ob} t - ½ 0.4 t²

at the point where they meet, the position of the two vehicles is the same

         0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²

let's reduce the speeds to the SI system

        v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s

        v_{ob} = 23.4 km / h = 6.5 m / s

        4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²

        0.2 t² - 2.5 t - 30 = 0

        t² - 12.5 t - 150 = 0

we solve the quadratic equation

       t = \frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150}  }{2}

       t = \frac{12.5 \  \pm 27.5}{2}

       t₁ = 20 s

       t₂ = -7.5 s

time must be a positive quantity so the correct result is t = 20 s

let's look for the distance

        x = 4 t + ½ 0.8 t²

        x = 4 20 + ½ 0.8 20²

        x = 240 m

8 0
3 years ago
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