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Assoli18 [71]
3 years ago
12

How much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330 m/sec?

Physics
2 answers:
Fittoniya [83]3 years ago
8 0

(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds

                                                                 (4.55 sec, rounded)

GaryK [48]3 years ago
4 0
It will take 4.54545455 minutes for thunder to travel 1,500 meters. Just divide 1,500 by 330
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When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at spee
Charra [1.4K]

Answer:

The correct option is C

Explanation:

From the question we are told that

  The initial speed of the rocket is  v_i = 100 m/s

    The speed of the rocket engine sound is V

    The final speed of the rocket is  v_f = 200 \ m/s

The speed of the sound at v_f would still remain V this because the speed of sound wave is constant and is not dependent on the speed of the observer(The mountain ) or the speed of the source (The rocket ).

  A clear example when  lightning strikes you will first see (that is because it travels at  the speed of light which is greater than the speed of sound) but it would take some time before you hear the sound of the   lightning

Here we see that the speed of the lightning(speed of sound) does not affect the speed of the sound it generates  

3 0
3 years ago
Two equally charged tiny spheres of mass 1.0 g are placed 2.0 cm apart. When released, they begin to accelerate away from each o
zhannawk [14.2K]

Answer:

The magnitude of the charge on each sphere is 0.135 μC

Explanation:

Given that,

Mass = 1.0

Distance = 2.0 cm

Acceleration = 414 m/s²

We need to calculate the magnitude of charge

Using newton's second law

F= ma

a=\dfrac{F}{m}

Put the value of F

a=\dfrac{kq^2}{mr^2}

Put the value into the formula

414=\dfrac{9\times10^{9}\times q^2}{1.0\times10^{-3}\times(2.0\times10^{-2})^2}

q^2=\dfrac{414\times1.0\times10^{-3}\times(2.0\times10^{-2})^2}{9\times10^{9}}

q^2=1.84\times10^{-14}

q=0.135\times10^{-6}\ C

q=0.135\ \mu C

Hence, The magnitude of the charge on each sphere is 0.135μC.

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3 years ago
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