1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
puteri [66]
3 years ago
7

How much money would need to be deposited into an account earning 5.75% interest compounded annually in order for the accumulate

d value at the end of 25 years to be $85,000? a. $75,425.52 b. $59,130.43 c. $21,009.20 d. $20,258.70
Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

c. $21009.20

Step-by-step explanation:

We are asked to find the principal amount of money that would be needed to deposited into an account earning 5.75% interest compounded annually in order for the accumulated value at the end of 25 years to be $85,000.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nT}, where,

A = Final amount after T years,

P = Principal amount,

r = Interest rate in decimal form,

n = Number of times interest is compounded per year,

T = Time in years.

Let us convert our given interest rate in decimal form.

5.75\%=\frac{5.75}{100}=0.0575

Upon substituting our given values in compound interest formula we will get,

\$85,000=P(1+\frac{0.0575}{1})^{1*25}

\$85,000=P(1+0.0575)^{25}

\$85,000=P(1.0575)^{25}

\$85,000=P*4.0458464965061301

Let us divide both sides of our equation by 4.0458464965061301.

\frac{\$85,000}{4.0458464965061301}=\frac{P*4.0458464965061301}{4.0458464965061301}

\$21009.20044134235=P

Upon rounding our answer to nearest hundredth we will get,

P\approx \$21009.20

Therefore, an amount of $21009.20 should be deposited in the account and option 'c' is the correct choice.

mihalych1998 [28]3 years ago
5 0
I will assume you are using compound interest. 

let the amount invested be x 

x(1.0575)^25 = 85000 
<span>x = 85000/1.0575^25 = $21,009.20</span>
You might be interested in
Find 2 consecutive odd integers sum of who's square is 290​ pls send fast
ELEN [110]

Answer:

<h3>Hence required integers are 11 and 13</h3>

Let x an odd positive integer

Then, according to question

x^2 +(x+2)^2=290

2x^2 +4x−286=0

x^2 +2x−143=0

x ^2+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13

Step-by-step explanation:

Hope it is helpful....

7 0
3 years ago
1. The present age of Visakha is x years. Find: I) How old was he 2 years before?​
bekas [8.4K]

Answer:

3 uwuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

6 0
3 years ago
How do you solve this problem
Savatey [412]
100+25x = y

Sorry gotta get 20 characters ignore this
6 0
3 years ago
Use an area model to show the product of 8x2.23 write your answer in standard form answer
mixas84 [53]

Answer:

17.84

Step-by-step explanation:

2.23

    8 x

-----------

17.84

4 0
3 years ago
Read 2 more answers
Which elements in a set below are integers?12,-3/4,5,-7,2.24,14/7,9
zhuklara [117]

Answer:

12, 5, -7, 14/7, 9

Step-by-step explanation:

Integers are numbers that are either positive or negative and are whole numbers (no decimals).

4 0
3 years ago
Other questions:
  • Enter the equation of the circle described below.<br> Center (3, -2), radius = 5
    14·2 answers
  • A haircut is 20 sales tax is 4.75 is 25 sufficient to cover the haircut cost with tax n tip %15 tip
    10·1 answer
  • How does the definition of percent help you write fraction and decimal equivalent
    13·1 answer
  • Anyone know the answer for this?
    13·1 answer
  • Rewrite the expression as a product of two factors. 72t+8
    15·1 answer
  • Jake and amber worm at McDonald's they each earn $8 per hour jake works three more hours then amber if jake and amber made a tot
    6·1 answer
  • PLEASE ANSWER BEING TIMED!!! 30 POINTS!!!!!!
    10·2 answers
  • Sally walks away from her
    14·2 answers
  • PLEASE HELP ASAP ILL GIVE BRAINLIEST
    7·1 answer
  • What is the sum of y and 7
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!