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mina [271]
3 years ago
6

luke bought 6 pretzels for himself and friends he spent a total of $13.50 let p represent the price of one pretzel​

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

6p=$13.50

Step-by-step explanation:

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A planning team expects that 3,600 people will take buses from the parking lots to the
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75 buses needed

Step-by-step explanation:

3,600 people /  each bus holds 48 people = 75

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In the parking lot , the number of Grey cars is 40% greater than the number of blue cars. If there are 98 grey cars, how many to
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I’m pretty sure it is 245 total cars
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Can someone help me with this
Anvisha [2.4K]

Answer:

D. \frac{{7}^{11} }{ {4}^{11} }

Step-by-step explanation:

( \frac{7}{4}) {}^{11} = \frac{7 {}^{11} }{4 {}^{11} }

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\frac{7 {}^{11} }{4 {}^{11} }

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Mary wants to hang a mirror in her room. The mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and
Umnica [9.8K]

Answer:

The quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.

Now to calculate the length and width of the frame consider following calculation,

Width of frame HG = x + DC + x  

Width of frame HG = x + 2 + x  

Width of frame HG =  2 + 2x  

2x is the addition of the thickness which is present on both side of mirror

Length of frame FG = x + BC + x

Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

Since it is an rectangular frame, so using the formula for area of rectangle

Area\:of\:rectangle = length \times width

Given that area of frame is 7\:ft^{2}

Substituting the value,

7 = \left(3+2x\right)\times \left(2+2x\right)

Therefore, the quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

8 0
2 years ago
Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i
bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1)  with respective to 'x'

\frac{dx}{dt} = 1+cost

differentiating equation (2)  with respective to 'y'

\frac{dy}{dt} = -sint

The length of curve is

\int\limits^\pi_\pi  {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt

\int\limits^\pi_\pi  \,   {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

\int\limits^\pi_\pi  \,   {\sqrt{(2+2cost } } \, dt

\sqrt{2} \int\limits^\pi_\pi  \,   {\sqrt{(1+1cost } } \, dt

again using formula, 1+cost = 2cos^2(t/2)

\sqrt{2} \int\limits^\pi _\pi  {\sqrt{2cos^2\frac{t}{2} } } \, dt

Taking common \sqrt{2} we get ,

\sqrt{2}\sqrt{2}  \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt

2(\int\limits^\pi _\pi  {cos\frac{t}{2} } \, dt

2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }

length of curve = 4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0
3 years ago
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