I'm sorry, I don't see the question. Could you please retake the photo in better quality so I could answer it? Thanks!
I'm a little confused by this. 1/2 is too big, but 1 1/2 is too small?
Answer:
c
Step-by-step explanation:
because there is a 3 in front of the root it is a cubed root since
2= square- the two is invisible but its there
3= cubed
Neither
Explanation
![f(x)=x^5+2x^4+3x-14](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E5%2B2x%5E4%2B3x-14)
Even:To do this, you take the function and plug –x in for x, and then simplify. If you end up with the exact same function that you started with (that is, if f (–x) = f (x), so all of the signs are the same), then the function is even.
Step 1
a)evaluate for -x
so
f(-x)
![\begin{gathered} f(-x)=(-x)^5+2(-x)^4+3(-x)-14 \\ f(-x)=-x^5+2x^4-3x-14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%28-x%29%3D%28-x%29%5E5%2B2%28-x%29%5E4%2B3%28-x%29-14%20%5C%5C%20f%28-x%29%3D-x%5E5%2B2x%5E4-3x-14%20%5Cend%7Bgathered%7D)
we conclude that
![f(x)\ne f(-x)](https://tex.z-dn.net/?f=f%28x%29%5Cne%20f%28-x%29)
so, the function is not even
Step 2
Determine whether the function satisfies
![f(x)=-f(-x)](https://tex.z-dn.net/?f=f%28x%29%3D-f%28-x%29)
If it does, it is odd function
replace
![\begin{gathered} x^5+2x^4+3x-14\text{ =? = -(}-x^5+2x^4-3x-14) \\ x^5+2x^4+3x-14\text{ =? = +}x^5-2x^4+3x+14 \\ x^5+2x^4+3x-14\text{ }\ne\text{ +}x^5-2x^4+3x+14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E5%2B2x%5E4%2B3x-14%5Ctext%7B%20%3D%3F%20%3D%20-%28%7D-x%5E5%2B2x%5E4-3x-14%29%20%5C%5C%20x%5E5%2B2x%5E4%2B3x-14%5Ctext%7B%20%3D%3F%20%3D%20%2B%7Dx%5E5-2x%5E4%2B3x%2B14%20%5C%5C%20x%5E5%2B2x%5E4%2B3x-14%5Ctext%7B%20%7D%5Cne%5Ctext%7B%20%2B%7Dx%5E5-2x%5E4%2B3x%2B14%20%5Cend%7Bgathered%7D)
therefore,
![f(x)\ne-f(-x)](https://tex.z-dn.net/?f=f%28x%29%5Cne-f%28-x%29)
so, this is not an odd function
so, the answer is
Neither
I hope this helps you
When ur dividing with exponents, u subtract the exponents
10^12 / 10^4 = 10^(12 - 4) = 10^8 <== ur exponent is 8