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2 years ago

Which choice could be the equation of a line parallel to the line represented by this equation 3x-2y=6 ?

1 answer:

6 0

You would change what the problem is equal to, so it could be 3x-2y=4 or any other answer as long as the coefficients are not changed.

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Is anyone good at paralleligram?!I will mark brainlest.for 13 points

Black_prince [1.1K]

Answer:

Y= 15

x = 12

Step-by-step explanation:

Okay, so the sides that are across from eachother, are always equal to eachother, in a parallelogram.

So, 5y-20 = 2y + 25

Next, you add 20 to both sides, and then subtract 2 from the right side, and subtract 2 from the left side ,and you get 3y = 45

divide 45 by 3 , and you get 15.

DO the same thing for the X's.

4 0

2 years ago

Use the expression to complete the statements. (0.5)10 (0.5)10 is the . (0.5) is the of (0.5)10. 10 is the of (0.5)10. A power i

RideAnS [48]

Question:

Use the expression to complete the statements.

$(0.5)^{10\\$

________ is the power .

(0.5) is the ________

A ______ is another way to write

Answer:

0.5 is the base

10 is the power

$(0.5)^{10\\ = (\frac{1}{2})^{10}$ -- another way to write

Step-by-step explanation:

Given

$(0.5)^{10\\$

Required

Fill ion the gaps

$(0.5)^{10\\$ is pronounced as; 0.5 raise to the power of 10

From the above statement, we can deduce the following:

0.5 is the base

10 is the power

Lastly, another way to write $(0.5)^{10\\$

Express 0.5 as a fraction

$(\frac{5}{10})^{10}$

Simplify the fraction

$(\frac{5/5}{10/5})^{10}$

$(\frac{1}{2})^{10}$

Hence:

$(0.5)^{10\\ = (\frac{1}{2})^{10}$

3 0

2 years ago

Read 2 more answers

Which equation would you use to find x?

Nitella [24]

You would use B to find X

8 0

3 years ago

57. What fraction of a quart is 1/2 cup?<br><br> 58. What fraction of a gallon is 1/2 cup?

densk [106]

57. 1/8

58. 1/32

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

3 0

2 years ago

Read 2 more answers

5. Solve using any method.<br> y = -x + 8<br> y=x+4

vlada-n [284]

Answer:

Step-by-step explanation:

$\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

$\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

7 0

3 years ago