To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
Answer: yes
Step-by-step explanation:
The vertex point is (0,4)
The two other points are (-2,0)(2,0)
Answer:
120i
Step-by-step explanation:
;i × i = -1....so hence
4i × (-5i) = -20 i^2...which is -20(-1) = 20....
then you multiply with 6i
20(6i) = 120i
Answer:
y=-1/3 x +2/3
Step-by-step explanation:
all steps are in picture
