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3 years ago

How do u measure to the nearest inch

2 answers:

6 0

If the answer is above 1/2 inch round it to 1 inch, if it is below 1/2 inch round it to 0, or the nearest number below it....hope it helps

Liula [17]3 years ago

3 0

<span>If the answer is above 1/2 inch round it to 1 inch, if it is below 1/2 inch round it to 0, or the nearest number below it....hope it helps

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If you have apples 14 banana And 20 potatoes, Find The:

sattari [20]

Step-by-step explanation:

Firs prime factorisation then we will find their GCF and it is 2

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3 years ago

Read 2 more answers

According to the Stack Overflow Developers Survey of 20184, 25.8% of developers are students.The probability that a developer is

murzikaleks [220]

Answer:

0.0326 = 3.26% probability that she is a student.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Woman developer

Event B: Student

Probability that the developer is a woman:

7.4% of 25.8%(students).

76.4% of 100 - 25.8 = 74.2%(not students). So

$P(A) = 0.074*0.258 + 0.764*0.742 = 0.58598$

Student and woman developer.

7.4% of 25.8%(students), so

$P(A \cap B) = 0.074*0.258 = 0.019092$

If we encounter a woman developer, what is the probability that she is a student

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.019092}{0.58598} = 0.0326$

0.0326 = 3.26% probability that she is a student.

5 0

3 years ago

According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what per

erastovalidia [21]

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

$\%Percentage = \frac{450}{500}$