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aleksley [76]
3 years ago
10

Let f(x)=6−1x+15x^2. Calculate the following values:

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

Step-by-step explanation:

To find f(a), replace x with a:  f(a)=6−1a+15a^2

To find f(a+h), replace x with (a+h):  f(a+h) = 6 -(a + h) + 15(a+h)^2

To find f(a+h)−f(a), expand f(a+h) as given above, and then subtract f(a):

f(a+h)−f(a) = 6 -a - h + 15(a^2 + 2ah + h^2)   -   [6 - a + 15a^2]

                   6 - a - h + 15a^2 + 30ah + 15h^2  -   [6 - a + 15a^2]

This simplifies to:   f(a+h)−f(a) = - h + 30ah + 15h^2  

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Answer:

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marta [7]

That's very interesting.  I had never thought about it before.
Let's look through all of the ten possible digits in that place,
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-- 0:
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-- 1:
    A number greater than 10 with a 1 in the units place could be
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-- 2:
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-- 3:
   A number greater than 10 with a 3 in the units place could be
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-- 4: 
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-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
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-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
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-- 9:
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So a number greater than 10 that IS a prime number COULD have
any of the digits  1,  3,  7,  or  9  in its units place.

It CAN't have a  0,  2,  4,  5,  6,  or  8 .

The only choice that includes all of the possibilities is  'A' .

4 0
3 years ago
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Answer:

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